Rejudge Progress:
1001: A+B again!!
Time Limit: 1000 MS Memory Limit: 65536 KBTotal Submit: 12697 Accepted: 2614 Page View: 14447
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Description
Your task is to calculate the sum of some integers.
Input
Input contains multiple test cases, and one case one line. Each case starts with an integer N( 0 < N<=500 ), and then N integers follow in the same line.
Output
For each test case you should output the sum of N integers in one line, and with one line of output for each line in input.
4 1 2 3 4
5 1 2 3 4 5
10
15
Hint
提供一个参考程序:
C语言:
#include"stdio.h" ///也可以使用 < >
int main()
{
int n,x,sum;
while(scanf("%d", &n) != EOF) /// EOF: end of file 文件结束标志
{
sum = 0;
while(n--)
{
scanf("%d", &x);
sum += x;
}
printf("%d\n", sum);
}
return 0;
}
C++:
#include"iostream" ///也可以使用 < >
using namespace std;
int main()
{
int n,x,sum;
while(cin >> n)
{
sum = 0;
while(n--)
{
cin >> x;
sum += x;
}
cout << sum << endl;
}
return 0;
}